❞ كتاب Solution Manual – Digital Design 4th Ed - MorrisMano P1-P294 ❝  ⏤ إم موريس مانو

❞ كتاب Solution Manual – Digital Design 4th Ed - MorrisMano P1-P294 ❝ ⏤ إم موريس مانو

Solution Manual – Digital Design 4th Ed - MorrisMano P1-P294

FOURTH EDITION
M. MORRIS MANO
California State University, Los Angeles
MICHAEL D. CILETTI
University of Colorado, Colorado Springs

Digital Design – Solution Manual. M. Mano. M.D. Ciletti, Copyright 2007, All rights reserved.
2
CHAPTER 1
1.1 Base-10: 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32
Octal: 20 21 22 23 24 25 26 27 30 31 32 33 34 35 36 37 40
Hex: 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F 20
Base-13 A B C 10 11 12 13 14 15 16 17 18 19 23 24 25 26
1.2 (a) 32,768 (b) 67,108,864 (c) 6,871,947,674
1.3 (4310)5 = 4 * 53 + 3 * 52 + 1 * 51 = 58010
(198)12 = 1 * 122 + 9 * 121 + 8 * 120 = 26010
(735)8 = 7 * 82 + 3 * 81 + 5 * 80 = 47710
(525)6 = 5 * 62 + 2 * 61 + 5 * 60 = 19710
1.4 14-bit binary: 11_1111_1111_1111
Decimal: 214 -1 = 16,38310
Hexadecimal: 3FFF16
1.5 Let b = base
(a) 14/2 = (b + 4)/2 = 5, so b = 6
(b) 54/4 = (5*b + 4)/4 = b + 3, so 5 * b = 52 – 4, and b = 8
(c) (2 *b + 4) + (b + 7) = 4b, so b = 11
1.6 (x – 3)(x – 6) = x2 –(6 + 3)x + 6*3 = x2 -11x + 22
Therefore: 6 + 3 = b + 1m so b = 8
Also, 6*3 = (18)10 = (22)8
1.7 68BE = 0110_1000_1011_1110 = 110_100_010_111_110 = (64276)8
1.8 (a) Results of repeated division by 2 (quotients are followed by remainders):
43110 = 215(1); 107(1); 53(1); 26(1); 13(0); 6(1) 3(0) 1(1)
Answer: 1111_10102 = FA16
(b) Results of repeated division by 16:
43110 = 26(15); 1(10) (Faster)
Answer: FA = 1111_1010
1.9 (a) 10110.01012 = 16 + 4 + 2 + .25 + .0625 = 22.3125
(b) 16.516 = 16 + 6 + 5*(.0615) = 22.3125
(c) 26.248 = 2 * 8 + 6 + 2/8 + 4/64 = 22.3125
© 2007 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained
from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording,
or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458.
إم موريس مانو - ❰ له مجموعة من المؤلفات أبرزها ❞ Introduction Digital Design M. Morris Mano ❝ ❞ Solution Manual – Digital Design 4th Ed - MorrisMano P1-P294 ❝ ❞ 10 – Digital Intergrated Circuts BY :M. Morris Mano ❝ ❞ 02 – Boolean Algebra and Logic Gates ❝ ❞ 12 – Standard Graphic Symbols BY :M. Morris Mano ❝ ❞ 13 – Index BY :M. Morris Mano ❝ ❞ Chapter 11 Laboratory Experiments with Standard ICs and FPCAs ❝ ❞ 09 – Asynchronous Sequential Logic :M. Morris Mano ❝ ❞ M. Morris Mano 01 – Digital Systems and Binary Numbers ❝ ❱
من الكتب التقنية والحاسوبية العامة - مكتبة كتب تقنية.

نُبذة عن الكتاب:
Solution Manual – Digital Design 4th Ed - MorrisMano P1-P294

2007م - 1442هـ
Solution Manual – Digital Design 4th Ed - MorrisMano P1-P294

FOURTH EDITION
M. MORRIS MANO
California State University, Los Angeles
MICHAEL D. CILETTI
University of Colorado, Colorado Springs

Digital Design – Solution Manual. M. Mano. M.D. Ciletti, Copyright 2007, All rights reserved.
2
CHAPTER 1
1.1 Base-10: 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32
Octal: 20 21 22 23 24 25 26 27 30 31 32 33 34 35 36 37 40
Hex: 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F 20
Base-13 A B C 10 11 12 13 14 15 16 17 18 19 23 24 25 26
1.2 (a) 32,768 (b) 67,108,864 (c) 6,871,947,674
1.3 (4310)5 = 4 * 53 + 3 * 52 + 1 * 51 = 58010
(198)12 = 1 * 122 + 9 * 121 + 8 * 120 = 26010
(735)8 = 7 * 82 + 3 * 81 + 5 * 80 = 47710
(525)6 = 5 * 62 + 2 * 61 + 5 * 60 = 19710
1.4 14-bit binary: 11_1111_1111_1111
Decimal: 214 -1 = 16,38310
Hexadecimal: 3FFF16
1.5 Let b = base
(a) 14/2 = (b + 4)/2 = 5, so b = 6
(b) 54/4 = (5*b + 4)/4 = b + 3, so 5 * b = 52 – 4, and b = 8
(c) (2 *b + 4) + (b + 7) = 4b, so b = 11
1.6 (x – 3)(x – 6) = x2 –(6 + 3)x + 6*3 = x2 -11x + 22
Therefore: 6 + 3 = b + 1m so b = 8
Also, 6*3 = (18)10 = (22)8
1.7 68BE = 0110_1000_1011_1110 = 110_100_010_111_110 = (64276)8
1.8 (a) Results of repeated division by 2 (quotients are followed by remainders):
43110 = 215(1); 107(1); 53(1); 26(1); 13(0); 6(1) 3(0) 1(1)
Answer: 1111_10102 = FA16
(b) Results of repeated division by 16:
43110 = 26(15); 1(10) (Faster)
Answer: FA = 1111_1010
1.9 (a) 10110.01012 = 16 + 4 + 2 + .25 + .0625 = 22.3125
(b) 16.516 = 16 + 6 + 5*(.0615) = 22.3125
(c) 26.248 = 2 * 8 + 6 + 2/8 + 4/64 = 22.3125
© 2007 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained
from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording,
or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458. .
المزيد..

تعليقات القرّاء:

Solution Manual – Digital Design 4th Ed - MorrisMano P1-P294

FOURTH EDITION
M. MORRIS MANO
California State University, Los Angeles
MICHAEL D. CILETTI
University of Colorado, Colorado Springs

Digital Design – Solution Manual. M. Mano. M.D. Ciletti, Copyright 2007, All rights reserved.
2
CHAPTER 1
1.1 Base-10: 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32
Octal: 20 21 22 23 24 25 26 27 30 31 32 33 34 35 36 37 40
Hex: 10 11 12 13 14 15 16 17 18 19 1A 1B 1C 1D 1E 1F 20
Base-13 A B C 10 11 12 13 14 15 16 17 18 19 23 24 25 26
1.2 (a) 32,768 (b) 67,108,864 (c) 6,871,947,674
1.3 (4310)5 = 4 * 53 + 3 * 52 + 1 * 51 = 58010
(198)12 = 1 * 122 + 9 * 121 + 8 * 120 = 26010
(735)8 = 7 * 82 + 3 * 81 + 5 * 80 = 47710
(525)6 = 5 * 62 + 2 * 61 + 5 * 60 = 19710
1.4 14-bit binary: 11_1111_1111_1111
Decimal: 214 -1 = 16,38310
Hexadecimal: 3FFF16
1.5 Let b = base
(a) 14/2 = (b + 4)/2 = 5, so b = 6
(b) 54/4 = (5*b + 4)/4 = b + 3, so 5 * b = 52 – 4, and b = 8
(c) (2 *b + 4) + (b + 7) = 4b, so b = 11
1.6 (x – 3)(x – 6) = x2 –(6 + 3)x + 6*3 = x2 -11x + 22
Therefore: 6 + 3 = b + 1m so b = 8
Also, 6*3 = (18)10 = (22)8
1.7 68BE = 0110_1000_1011_1110 = 110_100_010_111_110 = (64276)8
1.8 (a) Results of repeated division by 2 (quotients are followed by remainders):
43110 = 215(1); 107(1); 53(1); 26(1); 13(0); 6(1) 3(0) 1(1)
Answer: 1111_10102 = FA16
(b) Results of repeated division by 16:
43110 = 26(15); 1(10) (Faster)
Answer: FA = 1111_1010
1.9 (a) 10110.01012 = 16 + 4 + 2 + .25 + .0625 = 22.3125
(b) 16.516 = 16 + 6 + 5*(.0615) = 22.3125
(c) 26.248 = 2 * 8 + 6 + 2/8 + 4/64 = 22.3125
© 2007 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This publication is protected by Copyright and written permission should be obtained
from the publisher prior to any prohibited reproduction, storage in a retrieval system, or transmission in any form or by any means, electronic, mechanical, photocopying, recording,
or likewise. For information regarding permission(s), write to: Rights and Permissions Department, Pearson Education, Inc., Upper Saddle River, NJ 07458.



سنة النشر : 2007م / 1428هـ .
حجم الكتاب عند التحميل : 1.8 ميجا بايت .
نوع الكتاب : pdf.
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إم موريس مانو - M. Morris Mano

كتب إم موريس مانو ❰ له مجموعة من المؤلفات أبرزها ❞ Introduction Digital Design M. Morris Mano ❝ ❞ Solution Manual – Digital Design 4th Ed - MorrisMano P1-P294 ❝ ❞ 10 – Digital Intergrated Circuts BY :M. Morris Mano ❝ ❞ 02 – Boolean Algebra and Logic Gates ❝ ❞ 12 – Standard Graphic Symbols BY :M. Morris Mano ❝ ❞ 13 – Index BY :M. Morris Mano ❝ ❞ Chapter 11 Laboratory Experiments with Standard ICs and FPCAs ❝ ❞ 09 – Asynchronous Sequential Logic :M. Morris Mano ❝ ❞ M. Morris Mano 01 – Digital Systems and Binary Numbers ❝ ❱. المزيد..

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